Tuesday, 22 November 2016

Preparation Strategy for XAT 2017

Xavier Aptitude Test 2017 (XAT) is scheduled to be conducted on January 8, 2017. Candidates should fasten-up their belts and formulate preparation strategies as there is only a month to go. To achieve the best in the examination it is a must for all the candidates to start their preparation strategically and as early as possible.
Given below is the complete examination pattern and marking scheme to get familiar with and make a better preparation strategy.


You can read the full article here:Preparation Strategy for XAT 2017

Monday, 14 November 2016

Why is Children’s Day celebrated on 14th November?

Children’s day is celebrated in India on 14th of November, the birth date of Indian First Prime Minister, Jawaharlal Nehru, every year. But have you ever imagined why we celebrate this day as Children’s Day? Well, apart from being a good statesman, he was immensely fond of children. He was popular among the children as Chacha Nehru (Uncle Nehru) or Chachaji. According to his thoughts, he considers children as the future of a nation.
You can read the full article here:Why is Children’s Day celebrated on 14th November?

Tuesday, 8 November 2016

10 Must-Follow Tips to Prepare for CAT 2016

CAT, Common Admission Test is the most sought after examination. Almost every graduate who aspires to attain a post-graduate degree in management courses refers to this exam because it is the only MBA entrance examination, which is accepted by all Management institutes. Moreover, it is also the only one mode to get admission into the premium institutes of India, IIMs (Indian Institute of Management). CAT 2016 is scheduled to be held on 4th December 2016 by IIIM Bangalore.
You can read the full article here:10 Must-Follow Tips to Prepare for CAT 2016

CA CPT 2016 Exam Preparation Tips

CA CPT is a Common Proficiency Test which is an entry level test for Chartered Accountancy Course. CA CPT 2016 Examination will be held on 18 December 2016 in two different sessions by Institute of Charted Accountants of India (ICAI) to select eligible candidates. Students take this examination to become Chartered Accountants. Student’s skills on Accounting, Mercantile Laws, General Economics and Quantitative Aptitude will be evaluated through this examination.

You can read the full article here:CA CPT 2016 Exam Preparation Tips

Tuesday, 25 October 2016

Previous Year Question paper for class 10 Biology- 2011, ICSE – Robomateplus

Get these Previous Year Question Papers of  ICSE 10th Biology and kickstart your exam preparation! Download and solve the latest ICSE papers at your own convenience. Our experts have also provided detailed solutions to all these papers. Happy studying!

For ICSE 10th 2011 Biology Question Paper Click here.

For ICSE 10th 2011 Biology Solution Paper Click here.

Previous Year Question paper for class 10 Biology - 2012, ICSE – Robomateplus

Get these Previous Year Question Papers of  ICSE 10th Biology and kickstart your exam preparation! Download and solve the latest ICSE papers at your own convenience. Our experts have also provided detailed solutions to all these papers. Happy studying!

For ICSE 10th 2012 Biology Question Paper Click here.

For ICSE 10th 2012 Biology Solution Paper Click here.

Previous Year Question paper for class 10 Biology- 2013, ICSE – Robomateplus

Get these Previous Year Question Papers of  ICSE 10th Maths and kickstart your exam preparation! Download and solve the latest ICSE papers at your own convenience. Our experts have also provided detailed solutions to all these papers. Happy studying!

For ICSE 10th 2013 Biology Question Paper Click here.

For ICSE 10th 2013 BiologySolution Paper Click here.

Previous Year Question paper for class 10 Biology- 2014, ICSE – Robomateplus

Get these Previous Year Question Papers of  ICSE 10th Biology and kickstart your exam preparation! Download and solve the latest ICSE papers at your own convenience. Our experts have also provided detailed solutions to all these papers. Happy studying!

For ICSE 10th 2014 Biology Question Paper Click here.

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Previous Year Question paper for class 10 Biology - 2015, ICSE – Robomateplus

Get these Previous Year Question Papers of  ICSE 10th Biology and kickstart your exam preparation! Download and solve the latest ICSE papers at your own convenience. Our experts have also provided detailed solutions to all these papers. Happy studying!

For ICSE 10th 2015 Biology Question Paper Click here.

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Previous Year Question paper for class 10 Chemistry - 2011, ICSE – Robomateplus

Get these Previous Year Question Papers of  ICSE 10th Chemistry and kickstart your exam preparation! Download and solve the latest ICSE papers at your own convenience. Our experts have also provided detailed solutions to all these papers. Happy studying!

For ICSE 10th 2011 Chemistry Question Paper Click here.

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Previous Year Question paper for class 10 chemistry- 2012, ICSE – Robomateplus

Get these Previous Year Question Papers of  ICSE 10th Maths and kickstart your exam preparation! Download and solve the latest ICSE papers at your own convenience. Our experts have also provided detailed solutions to all these papers. Happy studying!

For ICSE 10th 2012 Chemistry Question Paper Click here.

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Previous Year Question paper for class 10 Chemistry- 2013, ICSE – Robomateplus

Get these Previous Year Question Papers of  ICSE 10th Maths and kickstart your exam preparation! Download and solve the latest ICSE papers at your own convenience. Our experts have also provided detailed solutions to all these papers. Happy studying!

For ICSE 10th 2013 Chemistry Question Paper Click here.

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Previous Year Question paper for class 10 Chemistry- 2014 ICSE – Robomateplus

Get these Previous Year Question Papers of  ICSE 10th Maths and kickstart your exam preparation! Download and solve the latest ICSE papers at your own convenience. Our experts have also provided detailed solutions to all these papers. Happy studying!

For ICSE 10th 2014 Chemistry Question Paper Click here.

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Previous Year Question paper for class 10 Chemistry- 2015, ICSE – Robomateplus

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For ICSE 10th 2015 Chemistry Question Paper Click here.

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Previous Year Question paper for class 10 Mathematics - 2011, ICSE – Robomateplus

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For ICSE 10th 2011 Maths Question Paper Click here.

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Previous Year Question paper for class 10 Mathematics - 2012, ICSE – Robomateplus

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Previous Year Question paper for class 10 Mathematics - 2013, ICSE – Robomateplus

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Previous Year Question paper for class 10 Mathematics - 2014, ICSE – Robomateplus

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Previous Year Question paper for class 10 Mathematics - 2015, ICSE – Robomateplus



Get these Previous Year Question Papers of  ICSE 10th Maths and kickstart your exam preparation! Download and solve the latest ICSE papers at your own convenience. Our experts have also provided detailed solutions to all these papers. Happy studying!

For ICSE 10th 2015 Maths Question Paper Click here. 

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Friday, 21 October 2016

New Changes in CA Course to be Introduced by ICAI

According to the Economic Times, the Institute of Chartered Accountants of India (ICAI), the exam conducting authority, has approached the Ministry of Corporate Affairs to improvise the CA curriculum, introduce electives, new subjects, and open book tests in a few papers.
“Globalisation has brought to the fore not only opportunities in areas of international and national financial reporting, finance, taxation, and corporate laws but also challenges to the chartered accountancy profession.” said M Devaraja Reddy, ICAI President.

You can read the full article here:New Changes in CA Course to be Introduced by ICAI

Monday, 17 October 2016

Tips to remember for a Personal Interview

Everyone who has cleared the written test and has been called for the interview is determined to succeed. However, the uncertainty of what’s going to happen is the biggest roadblock for aspirants who want to ace the MBA personal interview. Here some useful tips:
  • Be Punctual: If you really want to succeed in the interview then be at the venue almost 30 minutes before the scheduled time.
  • Dress-up like a Professional: Professionalism starts with your attire. Clothes build your personality, hence, choose the best formal attire for the interview. If you are a girl then leave all the accessories at home. Also, keep in mind that it is good to smell nice, but don’t smell like a bottle of perfume. Just smell pleasant.

You can read the full article here: Tips to remember for a Personal Interview

How MBA Interviews differ from regular ones?

The purpose of conducting interviews, MBA Admission Interview or Regular Interview, is to select the most appropriate candidate for the respective institute or job. However, there are few aspects that separate them. MBA Personal Interview is a little special among the other rounds as it requires elite treatment and you will also get the same.
You have qualified the primary level, i.e. the entrance test and now you are all set to face the interview panel. Here are some questions that may pop-up in your mind, and the major one is ‘How MBA Interviews differ from regular ones?’ Here, we have tried to explain the differences between them.
You can read the full article here: How MBA Interviews differ from regular ones?

How to prepare for MBA Admission interview?

To get admission to a renowned B-school you require hard work and dedication. Personal Interviews are conducted to evaluate the communication and interpersonal skills of aspirants. Moreover, a student’s confidence, personality, and leadership skills will be analyzed to offer admission. Hence, preparing for MBA Admission Personal Interview needs focused approach and ample knowledge about current affairs and general awareness. To prepare for a personal interview, aspirants can follow the below mentioned tips:
  • Do Research
Know the format of admissions committee for the personal interview. This will help you to anticipate questions so that you can prepare for the answers as per the format. Explain your story, why do you want to pursue the MBA course and also mention how this can help you in achieving your goals. Be honest. Don’t use drama or trivial talk. Be brief and straight to the point.


You can read the full article here: How to prepare for MBA Admission interview?

8 Tips To Crack Personal Interview for B-School Admission

Personal Interview round is conducted to check the interpersonal skills of aspirants.  This is the case whether you have applied for MBA Admission or a Job Opening. MBA (Master’s in Business Administration) is a post-graduate degree that is required to apply for premium positions. Hence, there are certain parameters on which the caliber of a candidate is judged such as communication skills, presentation of self and more. Listed here are 8 PI Tips for B-Schools:
  1. Be Confident: Confidence is a very important asset that one should possess. It should not be misconstrued as arrogance, which often results in overconfidence. There is a very thin line between confidence and arrogance. Learn to be confident and show it in your answers.

You can read the full article here: 8 Tips To Crack Personal Interview for B-School Admission

10 Most Common MBA Interview Questions

The toughest section among all the screening rounds is the personal interview. That is because there is no syllabus, no pattern and no definite queries that you can refer to. Interviewers focus on evaluating your overall personality and skills while conducting an MBA Personal Interview.
Students are required to have quality leadership skills. Although what the interviewers will ask you is uncertain, we have jotted down for you some of the usually asked questions.
  1. Tell Us Something about Yourself.
    Why do you want an MBA Degree?
This is one request the interviewers usually have. Here, you need to give a short description about yourself including family background, education qualifications and more.
Explain what motivates you to pursue a degree in management courses.

You can read the full article here:10 Most Common MBA Interview Questions

What’s new in JEE Advanced 2017

JEE Advanced 2017 is the premium engineering entrance examination conducts by IITs, every year. Lakhs of students appear in the examination to get admission in all the finest engineering colleges, Indian Institute of Technology (IITs) and ISM. For 2017, the examination dates and conducting authority has been announced. JEE Advanced 2017 will be conducted on 21 May 2017 by IIT Madras under the aegis of seven Zonal IITs. Although, the overall application and examination process will remain the same, some important changes have been introduced in the reservation, a number of appearing candidates, eligibility criteria and more. Here, we have listed what new changes have been introducing in JEE Advanced 2017.
 You can read the full article here:What’s new in JEE Advanced 2017


Thursday, 25 August 2016

KARNATAKA STATE BOARD XII PCMB Physics Demo Videos


Hello students today  we will discuss the concept of  magnetism and matter before  going to the concept  of  magnetism and matter  I would like to give you certain  key points  regarding the magnetism  that is  history of magnetism once magnets was hoarding  his  sheep in an area northern Greece  called magnesia  suddenly both the nail of his shoes and metal tip of his staff  become  firmly stuck to the large black rock on which he was standing . he was very curious to know fact behind it there for to find the source of attraction he dug up the earth and he finds load stones this is how the load stones look like . A load stones which contains magnetite and natural magnetic material Fe3O4 students keep in mind again a load stone which contains magnetite which is nothing but a natural magnetic material fe3O4. Okay fine .So the directional property of magnet was also known since ancient times  that is freely suspended  magnet and the magnet which placed on piece of cork allowed to float still on water always pointed in the north to south direction this is how can we recognize the direction of property of magnet  a freely suspended magnet  and the magnet which placed on a piece of cork  on floating still water north to south direction ok they have also use this magnet in many application one of the application will see now, you can look at the image the image is chariot with that magnetic idol is suspended the craft man build a chariot on which they place the magnetic figure which swiveled around so that the finger of the statuette on its  always pointed south. With this chariot huangti troops were able to attack enemy from the rear in thick fog and defeat them this was one of the application in the earlier days using magnets and the latest science suggest that moving charges or electric current produce magnetic field moving charges or electric current produce magnetic field this discovery was credited to the scientist oersted  ampere , Biot and savart . dear students now will discuss the common ideas regarding the magnetism  that is the first one is the earth behaves as a magnet  with magnetic field pointing approximately from geographical  south to geographical north . what is that mean  on the whole we can treat as the magnet  where the magnetic field pointing approximately  from geographic south to the geographic north next, when bar magnet is freely suspended it points the north south direction this property you know when the bar magnet freely suspended it always points in what north and south direction ok that tip which points the geographic north is called north pole and the tip which geographic sounds is called south pole u can observe the tip which point the geographic north is north pole and the tip of geographic south is south pole ok the next point is like an electrostatic here also you can get also properties likes poles ripple each other what does that mean if you bought two bar magnets of same poles , if u bought a bar magnets  of same poles each other those two bar magnet tend to ripple one and other why it so  because the between those two same poles repulsive force exist in the same way unlike pole attract each other that means if you bought two bar magnets of opposite poles those two bar magnets always attract each other and that is because of the attractive forces exist between the opposite poles so that on whole I can conclude like  poles ripples each other and unlike poles ripples  attract each other and next point is magnetic monopoles do not exist  what does mean magnetic monopoles do not exist  which is nothing but if u cut a bar into a  N equal pieces each one will be having both south and the north poles that means if u consider a bar magnet and make it into N slices in the number of slices each slices what u  have what time will be always facilitated with the two poles that is north pole south pole , north pole south pole  there for we can say that magnetic monopole do not exist ok the next point is it is possible  to make magnet out of iron and its alloys yes we can manufacture magnet with the help of iron and its alloys for example the manufacture of alnico magnets uses iron and its alloys alnico is nothing but what aluminum nickel and cobalt ok the further discussion will be in the next module . Till then keep  learning thank you.  

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KARNATAKA STATE BOARD XII PCMB maths Demo Videos


Hello students welcome to this new chapter probability. Where we are going to speak about condition of probability in this module. Now we should have strong knowledge about probability what you studied in your 11th std.  You were studied about definition of probability also you have studied about addition theorem rich to tell them. We have proceed further same concept of probability which is chapter for you in the 12th. Lets consider the definition of conditional probability , if E and F are two  events associated with a same sample space of a random experiment the condition of probability of the event E given that F has occurred is given by P of E given by F is equal to P of E intersection F divided by P of F where P of F is not equal to zero remember this is a formula of conditional probability now I will note taken on that E given F already seen  what about P of F given E what happen what will be happen there P of F given E is equal to P of F intersection E divided by what dived by P of F making sure the denominator is not zero so that is a note you have let me proceed further there are some properties of conditional probability let see one by one and we see proof of it as well the first property says probability of S given F  is equal to P of F given F is equal to one . The second one says probability A union B given F is equal to probability P of A given F + probability B given F – probability A intersection B  given F And third one says probability E compliment given F is equal to 1 – probability E given F this are the three properties let see solution one by one. Let me start with the first probability S given F I understand the condition of probability e given F is equal to E intersection by F what will S given F it will be P of S intersection F divided by P of F remember this what is after that should be in denominator S given F what is second should be in denominator. now what  about the  proceeding part of this S intersection F  what you understand for this  S stands for sample space and I know that F is a subset of sample space F is an event is a subset of sample space and what about the intersection  obviously it is F P of S intersection F,  P of F  divided by P of F it is 1 so I have got first part of first property , what about second part of first property P of F given F it is according the formula of  condition probability I can write it as P of F Intersection F divided by P of F and F intersection F  because F is Same as F it is contained  so I can write F itself  P of F  divided by P of F is equal to 1 so we have got proof of 1st property . let me go with the proof of second property  . let me start P of A union B given F according to condition probability formula we can write it as P of A union B intersection F divided by P of F now what about the numerator so I can use distributive law A union B intersection C is equal to A union C intersection B union C, same thing I will write here P of A union F intersection  B union c divided by  as it is P of A . now what about numerator use the addition theorem of probability and split the numerator  as it is what I get that I will get it as P of A intersection F + P of B intersection F – P of  A intersection B intersection F divided by P of F . now I will split it into three parts I will get it as P of A intersection F divide by P of A + P of B intersection F divided by P of A – P of A intersection B intersection F divided by P of F now I can recall the condition of probability . earlier we have seen  left hand side right in the right hand side now see the right hand side right the left hand side according to that the first term P of A given F  what is the second term P of B given F  third term will be p of A intersection B giving F and this is the proof of second property  I can take a note regarding the particular property  when A and B are mutually exclusive intersection is zero their for I  can get P of A union B giving P of A giving F + P of B giving F only A and B are mutually exclusive events . let me go the property no. 3 proof , we know that the first property P of S given F is equal to 1 also I know E union E compliment  any event union is compliment same as the sample space let me replace s by E union E’  do you think E union E’ are mutually exclusive yes they are mutually exclusive according to note mentioned earlier  A union B  giving F is equal to P of A giving F + P of B giving F , and I use that particular note P of E Giving F + P of E’ giving  F is equal to 1 there for the taking 1st term to right hand side  I get P of E’ giving F  is equal to 1- P of  E giving F that’s a required proof of the property so these are the 3 properties what we have conditional probability , Thank you . 

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KARNATAKA STATE BOARD XII PCMB Chemistry Demo Videos


Hello students welcome to module number 1 let us discuss something about solid state in this module we will discuss some introduction and classification of solids. My dear students we know that anything which occupied space and  has definite  mass as known as matter. A matter exist in a 3 physical state the first one is a solid  second one is liquid and third one is gas and these three physical state are inter convertible by changing the condition of temperature and pressure the solid on heating it is changes to a liquid. On heating the liquid changes into the gas by cooling the gas is converting to the liquid . and again cooling the liquid changes into the solid . There for the 3 states of matter are interconvertible by change in the temperature or pressure now let us scientist has discovered the two states of matter and these are plasma and Bose–Einstein condensate. The discovery of fifth state of matter was done by a great Indian scientist sattindranath Bose and well known scientist Albert Einstein. These 3 physical state of substance are mainly depends on two factor the first one is inter particles attractive forces and second one is thermal energy. The inter particles attractive forces constant particle tends to keep closer but thermal energy tends to keep them apart. Now students what are the solids the solids are the substance which have definite shape and definite volume. For example the TV, door , laptop these have definite shape and definite volume . These are the examples of the solids. Now what are the general  characteristics properties of solids are the first one  the solids have fixed mass, shape, volume  and density for example this box this box has definite mass definite volume definite mass definite shape also. In solids the intermolecular distance is very small take a look here the particles are closely packed there for intermolecular distance are very small. And if intermolecular distance are very small means what is the force of attraction .the force of attraction that is intermolecular force of attraction is very strong and coming to the last point the solids are hard, rigid and incompressible. These are properties of solid. Now the classification of solids based on the nature of orderly arrangement of constitute particles in 3 dimensions. The solids are classified into two types first one is crystalline solid and second one is amorphous solid now the students what are these crystalline solid and amorphous solid .their a long range orderly  arrangement of constituent particles in known as crystalline solid . and there is not long range orderly arrangement of constituent particles are known as amorphous solid .for crystalline solid examples are quartz , sodium chloride etc. for amorphous solid examples are polyvinyl chloride, glass fiber etc. now the properties of crystalline solid  the first property is crystalline solids have Sharp melting point and definite heat of fusion why crystalline solids have sharp melting point because the strength of all the bonds between the particles are equal there for crystalline solids have sharp melting point. Ice is an example of crystalline solid the melting point is zero degree Celsius coming to the second property of crystalline solid that is anisotropy. There is many properties which have different values in different directions for example the thermal conductivity , electrical conductivity , reflective index , mechanical strength are different along different directions in one directions the compositions of solid is  green purple , green purple and other it is purple, purple,  purple, purple since the composition of solid changes with direction has the values of physical  properties also changes therefor it exhibit work and isotropy nature or an isotropy now for this plain solid start and is appropriate in nature now what are the differences between crystalline and amorphous solid coming to the first parameter that is arrangement  there is a long range orderly arrangement of particles in crystalline solid in case amorphous solid that is short range of orderly arrangement i.e. there is no long range orderly arrangement of particles in case of amorphous solid the second property is melting point crystalline solids are have sharp melting point amorphous solid do not have sharp melting point  because the strength of all the bonds between the particles are not equal there for amorphous solid don’t have Sharpe melting point   and third property heat of fusion crystalline solids have definite heat of fusion and amorphous solid  no definite heat of fusion. And coming to the fourth anisotropy and isotropic nature .the crystalline solids are anisotropic in nature   and amorphous solids are isotropic in nature and coming to the fifth point nature. Crystalline solids are also known as true solid and amorphous solids are also known as a pseudo solid and coming to the last point shape crystalline solids have definite geometrical shape but amorphous solid has irregular shape. Thank you students.  

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KARNATAKA STATE BOARD XII PCMB Biology Demo Videos


Welcome students we are here with a beautiful and interesting chapter in biology i.e. health and disease. in this chapter we will talking about the basic different type of disease and then we followed by the very important system of our body i.e. the different mechanism which helps to fight those disease and finally brief talk about the different aspects of addiction. Now lets us talk about very first module in this module we will be dealing with the   erraticallypart what is basically health. Let us talk basically what is health and now it is very simple question for you students and very basic question but we all need to know what is health, yes let us taking an example. In this instance if you see the person here has got some disease yes we say that normally they are not healthy. Then does no disease means a healthy state. Let us talk about that now yes basically health doesnot simply mean the absence of disease or physical fitness then what is health? Yes  Health is basically defined using a 3 important dimension. Can you guess the three important dimension what it could be? Ya first one here is the physical. And second one is very important is the mental and third one is going to be a social. Yes student Let us talk about them in detail now basically health is defined as a state of complete physical well being. Yes student first of all as a state of complete health i.e physical well being. Next important thing and what is this indicate that a person is physically healthy but you know when they are bound with too much of stress or it can be any in balances in the body and it interfused called the depression. Yes student and they play very important role and here if u see the person has to be healthy then it is healthy only if they have what state yes I mean to say a complete state of what complete mental well begin and that mean the person should not have any short of depression also. Next important thing what is this? Yes I am talking about maintaining  good relationship with people in society. And here that is nothing but social well being let us try to summarized them now. Basically health is defined as a state of physical than the mental and social well being and very importantly and not merely absence of disease or infirmity. What is the infirmity? Yes infirmity meaning a state of weakness or debility. Now next important thing how do we remain a healthy? a very basic answer and very important answer here giving  is hygiene. What is the hygiene and write students is the science of health which actually aims at preserving then maintaining and the improving. Yes the health of the it is only individual, ya it is individual and the community as a whole that is how can maintain a hygienic condition. Next important thing here is how to remain a healthy or how to maintain a good  health and then very important thing practiced by us the first one , can you guesses the first one going to be , yes very right that is balanced diet . next important thing that is regular exercise  and yoga meditation etc. and next thing is maintain a personal  hygiene ,next is right attitude of mind and finally a cultivating a good habits  all if this maintain well help us to maintain a  good health now if this all are not maintained  what is going to leading do, yes it might your condition  called disease  what is disease let us now to defined that now disorder of structures  and functions basically other abnormal condition  all of them collectively is called as disease . Now in this module just we have to talk about a brief outline of that disease but later taking about some example also. Now here in this module we have discuss about the health and the basic concept of hygiene and also outline disease. Yes in the next module we will talking about type of disease. Ya  student we will right back in a next module. Bye then thank you.  

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KARNATAKA STATE BOARD XI PCMB Physics Demo Videos


Welcome dear students welcome to the chapter thermodynamics in this chapter we start with knowing the basic terminologies  in this module because understanding these basic terminologies  we can understand the chapter better ok let’s see what is the basic terminologies that we are going to studied in this module  very very basic  terms involved in this chapter first of all what do you mean by thermodynamics , thermodynamics  is a branch of physics which deals basically with the conversion of  heat energy into mechanical work or mechanical work into heat energy so it is the branch of physics which deals with a transfer energy from one place to another and conversion of heat energy into mechanical work or vice versa that is thermodynamics for me. Let’s see a simple example I got a cylinder me with me which is fitted with piston you can see on the screen and which has ideal gas in it. I supply heat energy how much I supply heat energy dQ amount of heat energy has been supplied and this energy what it does please observe that then you understand the meaning of thermodynamics this dQ supplied increases the volume of gas that is implies pushing the piston upward so dW amount of work is done    how much work will be done dW amount of work is done so heat energy supply is converted into work and that is what is thermodynamics  all about yeah let’s try to understand different types of system . what do you mean by thermodynamic system surrounding all that thermodynamic system is the quantity of matter certain quantity of matter having fixed identity and mass let’s see what is that A certain quantity of matter part of the matter having fixed identity and mass we call it thermodynamic system example, don’t think big about thermodynamic system is little water you’re got going to boil that and then that water becomes a system for you maybe I have gas in a cylinder that is a system for me look at this example water in a beaker may be 50 cc water Is that it is a system for you , you are expecting that , yes look at that In a container I’ve got gas that is a system for me having fixed identity and mass let’s see what is surrounding you must understand that anything other than the system in this universe become surrounding matter outside the system that becomes surroundings . so you have to understand that thermodynamic system continuously interacts the matter outside the system and that matter outside the system we are calling it as surrounding look at that delicious coffee may be a tea is presented in the cup that is the system for me now this system is a tea or coffee remember it interacts something outside matter outside and that part which is outside the system we are calling it as surrounding we go into different types of system right now what do you mean by open system , open system involves exchange of heat energy and matter between system and surrounding that system I m calling it as open system if there is exchange of heat and matter takes place between system and surrounding call that system as open system look at this piston and cylinder you can see in the picture which has gas in it and you supply the heat energy when you supply heat energy you can see that the gas expands work has been done yes excess heat energy is there what happened to the excess heat energy that will got . so it has got exchange of heat energy as well as matter and that system we are calling it is the open system lets go to the closed system means what a system in which you have got only action exchange of heat but not matter that is absolutely no matter exchange yes, if the exchange is only heat energy not the matter between the system and surrounding we call it as a closed system. cylinder provide with the piston having the ideal gas you supply heat energy remember only the heat energy exchange between the system and surrounding not the matter you can seen that work has been done but there is no matter to exchange let’s see what is that work done dW  amount of work done but no amount of matter exchanged between system and surrounding yes will know it isolated system no exchange of heat and matter between the system and surroundings let’s see that example no exchange of matter and heat between the system and surroundings look at this thermally isolated system nothing is going to inside neither heat not the matter the system is called as isolated system  non conducting wall … thank you.  

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KARNATAKA STATE BOARD XI PCMB Maths Limits Demo Videos


Hi I'm Hari Prasad let us start the chapter limits in this chapter we are going to learn how to find out the limit of the function and what do we mean by limit of a function let us start module number one in this particular module we are going to learn what is the meaning of the word tending to let us start the chapter now meaning of X x tends a is what we have to learn first so immediately the question that comes to my mind is what is the meaning of X tending 2 or X  tending to any particular number a in general so it can be particularly X tending to 2, X tending 3 something like that so what is the meaning of that does it mean x is equal 2  does it mean know that x is equal to something else so answer this particular question will consider the following example consider boy who always covers fifty percent of the total distance that means the boy covers five meter for the first time so where he will be he'll be at five meter mark the boy will cover all fifty percent of the remaining five meter that means he will cover all 2.5 meter for the second time third time he will cover 1.25 meter and so on if this is the case when the boy will be exactly on 10 meter mark can you predict the answer is the boy will be never on 10 meter mark but he's very close to 10 meter mark right similarly when we write X tending 2 we mean that X is very close to two but it is not equal 2 consider the number line we have minus 1 0 1 2 3 and so on when x tends 2 to it can be close to two when I say close to two it can be from the left side or it can be from the right side also write suppose if I say x tends 2 and if X's or close to 2 from the left side then it can take the following values can you get what are the values it can take x is equal to 1 .8 is possible it can take 1.9 yes it is close to 2 ,1.99 yes it can take these values right and one point nine nine nine yeah still very close to 2 and so on there are many infinitely many values that it can take but when X tends to 2 if X is close to two on the right then it can take the following values which are the values can you guess the point 2.8 can take it can take 2.2 it can take 2.1 and 2.01 so on it can take many other values right is so now the question is clear to us let us now talk in case of general elements like X and a, let X be a variable is the meaning of variable quantity which keeps changing and a be a constant with the meaning of constant quantity which has a fixed value right if X takes the value near Nearer  to a then we say that e tendens to a and  we write it as X arrow mark a We write it as does x tends to a note that in this case X cannot be equal to A  and we are not specifying any manner in which X should approach a that means it can approach to a from left as well as it can approach from right now when X tends to a from the left we have the following situation if X approaches a taking all values less than a but Nearer to a then we say that extends to a from the left we write this as extends to a and we put a small minus  over a this minus is not to be used in any of the calculation similarly when X tends to a from the right we have the following situation if X approaches a taking all the values greater than a but nearer to you a then we say that x tends to a from the right and rewrite it as x tends to a plus we write small plus sign over a  like this is the notation that you need to remember thank you.  

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KARNATAKA STATE BOARD XI PCMB Chemistry Demo Videos


Hello students welcome to the new chapter called state of matter in this chapter we are going to learn some interesting facts about the word matter so in this module will learn introduction to state of matter. let me start with the word matter  as we all know matter is anything that occupies the space possesses  mass for example this chair and table or a glass of water or some balloon  containing air so if I concentrate on this I come across with the new classification that matter  is going to get classified into three different types that is called solid other one liquid and one more is called gases so along with these three we having some more state of matter like plasma boseeinstein condensate, fermionic  condensate, quark condensate thought wave along with these three so let me concentrate on these three types called solid liquid  and gases . if u look at these pictures you can come across with the some interesting facts that the faster picture is tightly bond nothing but  solid second one is slightly distributed nothing but liquid last one is completely dispersed nothing but gases so by looking at this picture I think I can make out some interesting points with respect to this point number 1 if I concentrate on shape for solid this is perfect  If I concentrate on liquid there is no perfect shape if I concentrate on gas and similar to the liquid there is no shape for gas also. If I concentrate on volume solid has got volume liquid has got volume but there is no volume for gases. I got there intermolecular force of attraction and  on the word about that nothing but this particular word is very much essential for these two particular parameter for shape and volume so what is intermolecular force of attraction it is the attraction between two atoms if it is very much strong I will be having a solid shape but it is very ,very less then there is no shape and there is no volume so if I concentrate on intermolecular force of attraction it is very much strong in case of solids it is very weak in case of liquids and very week in case of gases so If I want a next point nothing but packing efficiency if I concentrate on packing solid are having closely packed structure if I concentrate on liquid is loosely packed if I concentrate on gases it is very loosely packed if I concentrate on next word called density we know the word density what is density it is nothing but mass by volume . if I concentrate on packing of this particular thing it is closely packed nothing but mass by volume is more in case of solids . so in case of liquid it is slightly less in case of gases it is very very less there for density is very high in case of for solids and it is very least  in case of gases and  is intermediate to solids and gases in case of liquids. So in the next point we are going to learn about the word called flow ability so the word of flow ability means that is the ability to flow which is maximum in case of gases and less in case of liquids least in case of solids. if I concentrate on compressibility it is nothing but ability to get compressed it is very high in case of gases and less in case of liquids  which is very least in case of solids . so there are main two parameters or condition by which I think these particular matters or wearing those two are temperature and pressure . if you concentrate on solid I can interconvert this solid into liquid just by heating and I can interconvert this liquid into gas just by heating so there is interesting phenomena that I can convert ice into water this water into steam just by heating so temperature, so the temperature is the main criteria to convert solid into liquid, liquid into gas similarly I can convert gas into liquid, liquid into solid by applying pressure . so these two are very interesting  condition by which I can convert a solid into liquid , liquid into gas now will concentrate on a new concept where and temperature will play a waiter roll to convert gas into liquid that means at the high temperature and low pressure gases will exist at the low temperature and high pressure liquid will exist there for transformation of liquid to gases can be done by wearing this two condition so we have to concentrate on high temperature low pressure of gases low temperature and high pressure for liquids .  


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KARNATAKA STATE BOARD XI PCMB Biology Demo Videos




Hello Students, I am Sarita, and, you and me today will study all about the plants. In studying the plants in module 1, will study about the tissues the plant tissues and students before we can go to the study of the tissues we need to study 2 terms that is why we need to study about the tissues and where are we studying about the tissues, look at that histology is the branch of biology where we study all about the tissues and why do we study about the tissues exactly to study about the internal structure and that is anatomy. The branch of biology that deals with the study of the internal structures with that the whole concept of plant tissues originated with work of the pioneers Nehemiah Grew as well as Marcello Malpighi of whom Nehemiah Grew later was called the father of plant anatomy and this rightly a 1mark question awfully asked in the boards students, who is the father of plant anatomy? And that’s Nehemiah Grew. Now what are plant tissues, there are group of cells or aggregation of cells which perform a common function and they have a common origin. Plant tissues basically can be classified into two types based upon the capacity to divide or not and are been classified as Maristem. Maristem which are those cells, which have the capacity to divide and again observe that students it’s a 1 mark question awfully asked in the board. So Maristem are those tissues which are capable of dividing have the capacity to divide they are constantly undergoing division. They had no other work other than dividing. The second group of tissues called them as permanent tissues and these are tissues which have stopped dividing or incapable of division and they are assigned with a particular function to take part in the plant body. Here we go on now. Before we study very clearly about the tissues, let us study 2 more terms one of them is differentiation. Now differentiation is refer students cells that is Meristematic tissues becoming assigned as a function that is less specialize cells become more specialized cells in order to perform a function, observe there Meristerms get themselves differentiated to give rise to Pyrencyma which a permanent tissue, observe that Meristems differentiate to become a permanent tissue. So they are form permanent tissues which are performing a function. I move on to the next term that is Dedefferentiation, now this reverse of differentiation, differentiated cells revert back to the dividing stage that means pyrencyma which is a permanent tissue becomes now a Meristematic in nature, look at that Meristerms permanent tissues divide or Dedefferentiate to become Meristerms that is permanent tissues which are assigned with the function, now start dividing and awfully happens in last trees for increase of growth, Thank You.  

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NEET & AIIMS 11th PCB Chemistry-Redox Reaction Demo Videos


Hello, students, let us continue our discussion on redox reactions. Now, in the last modules we will be discussing about calculation of equivalent weights of oxidising agents and reducing agents and we also defined a very important term z factor. Today we will continue to discuss some examples on equivalent weight calculation and then we will see two particular special cases FeC2O4 and Cu2S. Let us start with some examples.
Find the equivalent weight of KBrO3 and Br2 in the following reaction. Now, you can see that in this reaction 10 electrons are being exchanged. And we remember how we have to calculate z factor. So, let us begin with KBrO3. So, we can say that for 2 moles of KBrO3 number of electrons exchanged or rather gained in this case will be equal to 10. So, therefore we can say that for 1 mole of KBrO3, number of electrons gained. So, we can say that, so, we can say that for 1 mole of KBrO3, number of electrons gained will be equal to 10 by 2 that is 5. Now, the z factor of KBrO3 will be 5 and therefore equivalent weight will be equal to molecular weight of KBrO3 divided by 5. I am not getting the exact weight, I am just representing it symbolically and that is what is important. Now, for Br2 we see that the number of electrons exchanged are 10 and since there is only 1 mole of Br2 we need to see that there is only 10 electrons that we have to use. So, the z factor of bromine becomes 10 and equivalent weight will become molecular weight of bromine divided by 10.
Let us see the next example. When HNO3 is oxidised into ammonia means NH3, the equivalent weight of HNO3 will be how much? Now, HNO3 is being changed into ammonia. First of all we will write their oxidation number, nitrogen in HNO3 will be equal to plus 5, you know the algebraic method to calculate the oxidation numbers. Now, in ammonia the oxidation number of nitrogen is minus 3. So, we can see that, we can calculate the change in oxidation number, since there is only one atom of nitrogen it will be equal to plus 5 minus, minus minus 3 that is equal to plus 8. Keep in mind, change in oxidation number is initial oxidation number minus the final oxidation number. So, this 8 is there, this is what it will become the z factor and therefore equivalent weight is molecular weight divided by 8.
Let us see the next example. The equivalent weight of H2SO4 in the following reaction is. They have given us a redox reaction and in that they are asking for weight of H2SO4. Now, can I say that the z factor for H2SO4 will be equal to 2? Actually it would be wrong, why, because it is not an acid base reaction. It should be actually analysed like a redox reaction, which means we have to focus on the loss and gain of the electron. So, what should be your strategy? First we will find out the overall loss or gain of electrons in the redox reaction. It is like balancing, and with that process we have to get the loss or gain of electrons. To do this, we can either focus on SO2 or sodium dichromate that is Na2Cr2O7. Now, we will use this information to calculate the z factor of H2SO4. Just remember that there is only 1 mole of H2SO4 involved in the reaction. So, let us focus on the solution. The oxidation number of chromium in K2Cr2O7 is plus 6 and that in Cr2SO4 thrice is plus 3. Since there are two atoms of chromium we can see that the number of electrons exchanged overall will be equal to 6 and therefore we can say that for 1 mole of H2SO4 number of electrons exchanged will be also equal to 6. So, z factor of H2SO4 is 6 and the equivalent weight will be equal to molecular weight divided by 6. So, remember that in redox reaction acid and base equivalent weight will be got from loss or gain of electrons. Now, this calculation would also have been done, if you have just analysed SO2 to SO4 2 negative.
So, let us take a look at the next example. The equivalent weight of HNO3, molecular weight is 63, in the following reaction is. So, we have given a reaction between copper and HNO3 to give you copper nitrate and NO and H2. And we are having four options. Now, to analyse this reaction understand that HNO3 here is not just acting as an acid but it is also acting as an oxidising agent. So, HNO3 has dual roles, it is going to act as an oxidising agent and it will also provide the acidic medium. Now, we will find out the overall loss or gain of electrons. And to do this better would be copper because only oxidisation of copper is done. HNO3 is reducing, so, in HNO3 we have to observe NO very carefully. So, using this information we will calculate z factor and then we will get to the equivalent weight part. Let us see the solution. So, we can see that the oxidation number of Cu in copper is zero and that in copper nitrate is plus 2. Since there are 3 copper involved, we can see that the change in oxidation number is minus 6. Now, if we had to do NO, remember we have got only 2 NO corresponding to the change in oxidation number. So, we will find that nitrogen in HNO3 is plus 5 and that in NO is plus 2. So, the change in oxidation number is plus 6. Even if I do through copper or from HNO3 that means NO, from both the loss and gain of oxidation number will be 6 and it should be like that. So, number of electrons exchanged overall is 6 and therefore we can say for 8 moles of HNO3 number of electrons is equal to 6. For 1 mole of HNO3 it will be 6 by 8 that is 3 by 4. So, equivalent weight will be equal to molecular weight divided 3 by 4 or we can say it will be 63 times 4 by 3.
Now, let us focus on some special cases. We will focus on ferrous oxalate, FeC2O4. FeC2O4 is a good reducing agent. Now Fe2 positive is oxidised to Fe3 positive. Now, in this reaction we can see on the reactant side the charge is 2 positive and on the product side the charge is 3 positive. Now, to balance the charge since atoms are already balanced, to balance the charge we simply need to add an electron to the product side. Now, C2O4 negative 2 is oxidised to CO2 and we can see that here we will have to balance the atoms first. So, we just multiple the product side by 2. Now, to balance the charge, reactant side has got 2 negative charge and product side has 0. So, to balance the charge we simply add 2 electrons to the product side. Now, I am seeing both the reactions here that overall FeC2O4 both the components are oxidised. So, FeC2O4 overall loses a total of 3 electrons and hence equivalent weight of FeC2O4 will be equal to molecular weight divided by 3.
Now, let us see another special case, Cu2S, cupra sulphide. It is also a good reducing agent. Now, in this case Cu positive is oxidised to Cu 2positive. Again we will balance the charge. On the reactant side charge is 1 positive and on the product side charge is 2 positive. So, to balance the charge, we simply add an electron to the product side. Now, since there are 2 copper, we can say overall 2 electrons are lost for copper. Now, sulphide iron is oxidised to SO2. Now, first we will balance the atoms. So to do that, we have to add 2 H2O on the reactant side to balance the oxygen and 4H positive on the product side. Here we have assumed that medium is acidic in nature. So, we add these and then to balance the charge we see that the reactant side has a total charge of 2 negative and product side has 4 positive. To do this, we will now add 6 electrons to the product side and this balances the charge. So, 2 electrons of copper and 6 sulphide iron. So, Cu2S loses the total of 8 electrons and hence its equivalent weight will be equal to molecular weight divided by 8.
Thank you.  

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