Chitale’s Personalised Learning Center – CPLC, operational since 2002, has been the leading institute for coaching MBA aspirants in Mumbai.With over 200 hours of classroom training, the CAT program, addresses all aspects of CAT- Quant, Verbal, DI/reasoning and GK. The program is comprehensive and prepares students for XAT, IIFT, CET, NMAT, SNAP, TISS, CMAT and most Indian management entrance exams. Website:www.cplc.net.in
Tuesday, 22 November 2016
Preparation Strategy for XAT 2017
Xavier Aptitude Test 2017 (XAT) is scheduled to be conducted on January 8, 2017. Candidates should fasten-up their belts and formulate preparation strategies as there is only a month to go. To achieve the best in the examination it is a must for all the candidates to start their preparation strategically and as early as possible.
Monday, 14 November 2016
Why is Children’s Day celebrated on 14th November?
Children’s day is celebrated in India on 14th of November, the birth date of Indian First Prime Minister, Jawaharlal Nehru, every year. But have you ever imagined why we celebrate this day as Children’s Day? Well, apart from being a good statesman, he was immensely fond of children. He was popular among the children as Chacha Nehru (Uncle Nehru) or Chachaji. According to his thoughts, he considers children as the future of a nation.
You can read the full article here:Why is Children’s Day celebrated on 14th November?
Tuesday, 8 November 2016
10 Must-Follow Tips to Prepare for CAT 2016
CAT, Common Admission Test is the most sought after examination. Almost every graduate who aspires to attain a post-graduate degree in management courses refers to this exam because it is the only MBA entrance examination, which is accepted by all Management institutes. Moreover, it is also the only one mode to get admission into the premium institutes of India, IIMs (Indian Institute of Management). CAT 2016 is scheduled to be held on 4th December 2016 by IIIM Bangalore.
You can read the full article here:10
Must-Follow Tips to Prepare for CAT 2016
CA CPT 2016 Exam Preparation Tips
CA CPT is a Common Proficiency Test which is an entry level test for Chartered Accountancy Course. CA CPT 2016 Examination will be held on 18 December 2016 in two different sessions by Institute of Charted Accountants of India (ICAI) to select eligible candidates. Students take this examination to become Chartered Accountants. Student’s skills on Accounting, Mercantile Laws, General Economics and Quantitative Aptitude will be evaluated through this examination.
You can read the full article here:CA CPT 2016 Exam Preparation Tips
Tuesday, 25 October 2016
Previous Year Question paper for class 10 Biology- 2011, ICSE – Robomateplus
Get these Previous Year Question Papers of ICSE 10th Biology and kickstart your
exam preparation! Download and solve the latest ICSE papers at your own
convenience. Our experts have also provided detailed solutions to all these
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For ICSE 10th 2011 Biology Question Paper Click here.
For ICSE 10th 2011 Biology Solution Paper Click here.
Previous Year Question paper for class 10 Biology - 2012, ICSE – Robomateplus
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exam preparation! Download and solve the latest ICSE papers at your own
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papers. Happy studying!
For ICSE 10th 2012 Biology Question Paper Click here.
For ICSE 10th 2012 Biology Solution Paper Click here.
Previous Year Question paper for class 10 Biology- 2013, ICSE – Robomateplus
Get these Previous Year Question Papers of ICSE 10th Maths and kickstart your
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For ICSE 10th 2013 Biology Question Paper Click here.
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Previous Year Question paper for class 10 Biology- 2014, ICSE – Robomateplus
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Previous Year Question paper for class 10 Biology - 2015, ICSE – Robomateplus
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Previous Year Question paper for class 10 Chemistry - 2011, ICSE – Robomateplus
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Previous Year Question paper for class 10 chemistry- 2012, ICSE – Robomateplus
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Previous Year Question paper for class 10 Chemistry- 2013, ICSE – Robomateplus
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For ICSE 10th 2013 Chemistry Question Paper Click here.
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Previous Year Question paper for class 10 Chemistry- 2014 ICSE – Robomateplus
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Previous Year Question paper for class 10 Chemistry- 2015, ICSE – Robomateplus
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Friday, 21 October 2016
New Changes in CA Course to be Introduced by ICAI
According to the Economic Times, the Institute of Chartered Accountants of India (ICAI), the exam conducting authority, has approached the Ministry of Corporate Affairs to improvise the CA curriculum, introduce electives, new subjects, and open book tests in a few papers.
“Globalisation has brought to the fore not only opportunities in areas of international and national financial reporting, finance, taxation, and corporate laws but also challenges to the chartered accountancy profession.” said M Devaraja Reddy, ICAI President.
“Globalisation has brought to the fore not only opportunities in areas of international and national financial reporting, finance, taxation, and corporate laws but also challenges to the chartered accountancy profession.” said M Devaraja Reddy, ICAI President.
You can read the full article here:New Changes in CA Course to be Introduced by ICAI
Monday, 17 October 2016
Tips to remember for a Personal Interview
Everyone who has cleared the written test and has been called for the interview is determined to succeed. However, the uncertainty of what’s going to happen is the biggest roadblock for aspirants who want to ace the MBA personal interview. Here some useful tips:
- Be Punctual: If you really want to succeed in the interview then be at the venue almost 30 minutes before the scheduled time.
- Dress-up like a Professional: Professionalism starts with your attire. Clothes build your personality, hence, choose the best formal attire for the interview. If you are a girl then leave all the accessories at home. Also, keep in mind that it is good to smell nice, but don’t smell like a bottle of perfume. Just smell pleasant.
You can read the full article here: Tips to remember for a Personal Interview
How MBA Interviews differ from regular ones?
The purpose of conducting interviews, MBA Admission Interview or Regular Interview, is to select the most appropriate candidate for the respective institute or job. However, there are few aspects that separate them. MBA Personal Interview is a little special among the other rounds as it requires elite treatment and you will also get the same.
You have qualified the primary level, i.e. the entrance test and now you are all set to face the interview panel. Here are some questions that may pop-up in your mind, and the major one is ‘How MBA Interviews differ from regular ones?’ Here, we have tried to explain the differences between them.
You can read the full article here: How MBA Interviews differ from regular ones?
How to prepare for MBA Admission interview?
To get admission to a renowned B-school you require hard work and dedication. Personal Interviews are conducted to evaluate the communication and interpersonal skills of aspirants. Moreover, a student’s confidence, personality, and leadership skills will be analyzed to offer admission. Hence, preparing for MBA Admission Personal Interview needs focused approach and ample knowledge about current affairs and general awareness. To prepare for a personal interview, aspirants can follow the below mentioned tips:
- Do Research
Know the format of admissions committee for the personal interview. This will help you to anticipate questions so that you can prepare for the answers as per the format. Explain your story, why do you want to pursue the MBA course and also mention how this can help you in achieving your goals. Be honest. Don’t use drama or trivial talk. Be brief and straight to the point.
You can read the full article here: How to prepare for MBA Admission interview?
8 Tips To Crack Personal Interview for B-School Admission
Personal Interview round is conducted to check the interpersonal skills of aspirants. This is the case whether you have applied for MBA Admission or a Job Opening. MBA (Master’s in Business Administration) is a post-graduate degree that is required to apply for premium positions. Hence, there are certain parameters on which the caliber of a candidate is judged such as communication skills, presentation of self and more. Listed here are 8 PI Tips for B-Schools:
- Be Confident: Confidence is a very important asset that one should possess. It should not be misconstrued as arrogance, which often results in overconfidence. There is a very thin line between confidence and arrogance. Learn to be confident and show it in your answers.
You can read the full article here: 8 Tips To Crack Personal Interview for B-School Admission
10 Most Common MBA Interview Questions
The toughest section among all the screening rounds is the personal interview. That is because there is no syllabus, no pattern and no definite queries that you can refer to. Interviewers focus on evaluating your overall personality and skills while conducting an MBA Personal Interview.
Students are required to have quality leadership skills. Although what the interviewers will ask you is uncertain, we have jotted down for you some of the usually asked questions.
- Tell Us Something about Yourself.
Why do you want an MBA Degree?
This is one request the interviewers usually have. Here, you need to give a short description about yourself including family background, education qualifications and more.
Explain what motivates you to pursue a degree in management courses.
You can read the full article here:10 Most Common MBA Interview Questions
What’s new in JEE Advanced 2017
JEE Advanced 2017 is the premium engineering entrance examination conducts by IITs, every year. Lakhs of students appear in the examination to get admission in all the finest engineering colleges, Indian Institute of Technology (IITs) and ISM. For 2017, the examination dates and conducting authority has been announced. JEE Advanced 2017 will be conducted on 21 May 2017 by IIT Madras under the aegis of seven Zonal IITs. Although, the overall application and examination process will remain the same, some important changes have been introduced in the reservation, a number of appearing candidates, eligibility criteria and more. Here, we have listed what new changes have been introducing in JEE Advanced 2017.
Wednesday, 28 September 2016
Thursday, 25 August 2016
KARNATAKA STATE BOARD XII PCMB Physics Demo Videos
Hello students today we will discuss the concept of magnetism and matter before going to the concept of
magnetism and matter I would like
to give you certain key points regarding the magnetism that is history of magnetism once magnets was hoarding his
sheep in an area northern Greece
called magnesia suddenly both the
nail of his shoes and metal tip of his staff become
firmly stuck to the large black rock on which he was standing . he was
very curious to know fact behind it there for to find the source of attraction
he dug up the earth and he finds load stones this is how the load stones look
like . A load stones which contains magnetite and natural magnetic material
Fe3O4 students keep in mind again a load stone which contains magnetite which
is nothing but a natural magnetic material fe3O4. Okay fine .So the directional
property of magnet was also known since ancient times that is freely suspended magnet and the magnet which placed on piece
of cork allowed to float still on water always pointed in the north to south
direction this is how can we recognize the direction of property of magnet a freely suspended magnet and the magnet which placed on a piece of
cork on floating still water north to
south direction ok they have also use this magnet in many application one of
the application will see now, you can look at the image the image is chariot
with that magnetic idol is suspended the craft man build a chariot on which
they place the magnetic figure which swiveled around so that the finger of the
statuette on its always pointed south.
With this chariot huangti troops were able to attack enemy from the rear in
thick fog and defeat them this was one of the application in the earlier days
using magnets and the latest science suggest that moving charges or electric
current produce magnetic field moving charges or electric current produce
magnetic field this discovery was credited to the scientist oersted ampere , Biot and savart . dear students now
will discuss the common ideas regarding the magnetism that is the first one is the earth behaves as
a magnet with magnetic field pointing
approximately from geographical south to
geographical north . what is that mean
on the whole we can treat as the magnet
where the magnetic field pointing approximately from geographic south to the geographic north
next, when bar magnet is freely suspended it points the north south direction
this property you know when the bar magnet freely suspended it always points in
what north and south direction ok that tip which points the geographic north is
called north pole and the tip which geographic sounds is called south pole u
can observe the tip which point the geographic north is north pole and the tip
of geographic south is south pole ok the next point is like an electrostatic
here also you can get also properties likes poles ripple each other what does
that mean if you bought two bar magnets of same poles , if u bought a bar
magnets of same poles each other those
two bar magnet tend to ripple one and other why it so because the between those two same poles
repulsive force exist in the same way unlike pole attract each other that means
if you bought two bar magnets of opposite poles those two bar magnets always
attract each other and that is because of the attractive forces exist between
the opposite poles so that on whole I can conclude like poles ripples each other and unlike poles
ripples attract each other and next
point is magnetic monopoles do not exist
what does mean magnetic monopoles do not exist which is nothing but if u cut a bar into
a N equal pieces each one will be having
both south and the north poles that means if u consider a bar magnet and make
it into N slices in the number of slices each slices what u have what time will be always facilitated
with the two poles that is north pole south pole , north pole south pole there for we can say that magnetic monopole
do not exist ok the next point is it is possible to make magnet out of iron and its alloys yes
we can manufacture magnet with the help of iron and its alloys for example the
manufacture of alnico magnets uses iron and its alloys alnico is nothing but
what aluminum nickel and cobalt ok the further discussion will be in the next
module . Till then keep learning thank
you.
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KARNATAKA STATE BOARD XII PCMB maths Demo Videos
Hello
students welcome to this new chapter probability. Where we are going to speak
about condition of probability in this module. Now we should have strong
knowledge about probability what you studied in your 11th std. You were studied about definition of
probability also you have studied about addition theorem rich to tell them. We
have proceed further same concept of probability which is chapter for you in
the 12th. Lets consider the definition of conditional probability ,
if E and F are two events associated
with a same sample space of a random experiment the condition of probability of
the event E given that F has occurred is given by P of E given by F is equal to
P of E intersection F divided by P of F where P of F is not equal to zero
remember this is a formula of conditional probability now I will note taken on
that E given F already seen what about P
of F given E what happen what will be happen there P of F given E is equal to P
of F intersection E divided by what dived by P of F making sure the denominator
is not zero so that is a note you have let me proceed further there are some
properties of conditional probability let see one by one and we see proof of it
as well the first property says probability of S given F is equal to P of F given F is equal to one .
The second one says probability A union B given F is equal to probability P of
A given F + probability B given F – probability A intersection B given F And third one says probability E
compliment given F is equal to 1 – probability E given F this are the three
properties let see solution one by one. Let me start with the first probability
S given F I understand the condition of probability e given F is equal to E
intersection by F what will S given F it will be P of S intersection F divided
by P of F remember this what is after that should be in denominator S given F
what is second should be in denominator. now what about the
proceeding part of this S intersection F
what you understand for this S
stands for sample space and I know that F is a subset of sample space F is an
event is a subset of sample space and what about the intersection obviously it is F P of S intersection F, P of F
divided by P of F it is 1 so I have got first part of first property ,
what about second part of first property P of F given F it is according the
formula of condition probability I can
write it as P of F Intersection F divided by P of F and F intersection F because F is Same as F it is contained so I can write F itself P of F
divided by P of F is equal to 1 so we have got proof of 1st
property . let me go with the proof of second property . let me start P of A union B given F
according to condition probability formula we can write it as P of A union B
intersection F divided by P of F now what about the numerator so I can use
distributive law A union B intersection C is equal to A union C intersection B union
C, same thing I will write here P of A union F intersection B union c divided by as it is P of A . now what about numerator
use the addition theorem of probability and split the numerator as it is what I get that I will get it as P
of A intersection F + P of B intersection F – P of A intersection B intersection F divided by P
of F . now I will split it into three parts I will get it as P of A
intersection F divide by P of A + P of B intersection F divided by P of A – P
of A intersection B intersection F divided by P of F now I can recall the
condition of probability . earlier we have seen
left hand side right in the right hand side now see the right hand side
right the left hand side according to that the first term P of A given F what is the second term P of B given F third term will be p of A intersection B giving
F and this is the proof of second property
I can take a note regarding the particular property when A and B are mutually exclusive
intersection is zero their for I can get
P of A union B giving P of A giving F + P of B giving F only A and B are mutually
exclusive events . let me go the property no. 3 proof , we know that the first
property P of S given F is equal to 1 also I know E union E compliment any event union is compliment same as the
sample space let me replace s by E union E’
do you think E union E’ are mutually exclusive yes they are mutually
exclusive according to note mentioned earlier
A union B giving F is equal to P
of A giving F + P of B giving F , and I use that particular note P of E Giving
F + P of E’ giving F is equal to 1 there
for the taking 1st term to right hand side
I get P of E’ giving F is equal
to 1- P of E giving F that’s a required
proof of the property so these are the 3 properties what we have conditional
probability , Thank you .
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KARNATAKA STATE BOARD XII PCMB Chemistry Demo Videos
Hello students welcome to module number
1 let us discuss something about solid state in this module we will discuss
some introduction and classification of solids. My dear students we know that anything
which occupied space and has
definite mass as known as matter. A
matter exist in a 3 physical state the first one is a solid second one is liquid and third one is gas and
these three physical state are inter convertible by changing the condition of
temperature and pressure the solid on heating it is changes to a liquid. On heating
the liquid changes into the gas by cooling the gas is converting to the liquid
. and again cooling the liquid changes into the solid . There for the 3 states
of matter are interconvertible by change in the temperature or pressure now let
us scientist has discovered the two states of matter and these are plasma and Bose–Einstein
condensate. The discovery of fifth state of matter was done by a great Indian scientist
sattindranath Bose and well known scientist Albert Einstein. These 3 physical state of substance are mainly depends on two factor
the first one is inter particles attractive forces and second one is thermal energy.
The inter particles attractive forces constant particle tends to keep closer
but thermal energy tends to keep them apart. Now students what are the solids
the solids are the substance which have definite shape and definite volume. For
example the TV, door , laptop these have definite shape and definite volume . These
are the examples of the solids. Now what are the general characteristics properties of solids are the
first one the solids have fixed mass,
shape, volume and density for example
this box this box has definite mass definite volume definite mass definite shape
also. In solids the intermolecular distance is very small take a look here the
particles are closely packed there for intermolecular distance are very small.
And if intermolecular distance are very small means what is the force of
attraction .the force of attraction that is intermolecular force of attraction
is very strong and coming to the last point the solids are hard, rigid and
incompressible. These are properties of solid. Now the classification of solids
based on the nature of orderly arrangement of constitute particles in 3 dimensions.
The solids are classified into two types first one is crystalline solid and
second one is amorphous solid now the students what are these crystalline solid
and amorphous solid .their a long range orderly
arrangement of constituent particles in known as crystalline solid . and
there is not long range orderly arrangement of constituent particles are known
as amorphous solid .for crystalline solid examples are quartz , sodium chloride
etc. for amorphous solid examples are polyvinyl chloride, glass fiber etc. now
the properties of crystalline solid the
first property is crystalline solids have Sharp melting point and definite heat
of fusion why crystalline solids have sharp melting point because the strength
of all the bonds between the particles are equal there for crystalline solids
have sharp melting point. Ice is an example of crystalline solid the melting
point is zero degree Celsius coming to the second property of crystalline solid
that is anisotropy. There is many properties which have different values in
different directions for example the thermal conductivity , electrical
conductivity , reflective index , mechanical strength are different along
different directions in one directions the compositions of solid is green purple , green purple and other it is
purple, purple, purple, purple since the
composition of solid changes with direction has the values of physical properties also changes therefor it exhibit
work and isotropy nature or an isotropy now for this plain solid start and is
appropriate in nature now what are the differences between crystalline and
amorphous solid coming to the first parameter that is arrangement there is a long range orderly arrangement of
particles in crystalline solid in case amorphous solid that is short range of
orderly arrangement i.e. there is no long range orderly arrangement of
particles in case of amorphous solid the second property is melting point
crystalline solids are have sharp melting point amorphous solid do not have
sharp melting point because the strength
of all the bonds between the particles are not equal there for amorphous
solid don’t have Sharpe melting point and third property heat of fusion crystalline
solids have definite heat of fusion and amorphous solid no definite heat of fusion. And coming to the
fourth anisotropy and isotropic nature .the crystalline solids are anisotropic
in nature and amorphous solids are isotropic
in nature and coming to the fifth point nature. Crystalline solids are also
known as true solid and amorphous solids are also known as a pseudo solid and
coming to the last point shape crystalline solids have definite geometrical
shape but amorphous solid has irregular shape. Thank you students.
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KARNATAKA STATE BOARD XII PCMB Biology Demo Videos
Welcome
students we are here with a beautiful and interesting chapter in biology i.e.
health and disease. in this chapter we will talking about the basic different type
of disease and then we followed by the very important system of our body i.e.
the different mechanism which helps to fight those disease and finally brief
talk about the different aspects of addiction. Now lets us talk about very
first module in this module we will be dealing with the erraticallypart what is basically health. Let
us talk basically what is health and now it is very simple question for you
students and very basic question but we all need to know what is health, yes
let us taking an example. In this instance if you see the person here has got
some disease yes we say that normally they are not healthy. Then does no
disease means a healthy state. Let us talk about that now yes basically health
doesnot simply mean the absence of disease or physical fitness then what is health?
Yes Health is basically defined using a
3 important dimension. Can you guess the three important dimension what it
could be? Ya first one here is the physical. And second one is very important
is the mental and third one is going to be a social. Yes student Let us talk
about them in detail now basically health is defined as a state of complete
physical well being. Yes student first of all as a state of complete health i.e
physical well being. Next important thing and what is this indicate that a
person is physically healthy but you know when they are bound with too much of stress
or it can be any in balances in the body and it interfused called the
depression. Yes student and they play very important role and here if u see the
person has to be healthy then it is healthy only if they have what state yes I
mean to say a complete state of what complete mental well begin and that mean
the person should not have any short of depression also. Next important thing
what is this? Yes I am talking about maintaining good relationship with people in society. And here
that is nothing but social well being let us try to summarized them now.
Basically health is defined as a state of physical than the mental and social
well being and very importantly and not merely absence of disease or infirmity.
What is the infirmity? Yes infirmity meaning a state of weakness or debility.
Now next important thing how do we remain a healthy? a very basic answer and
very important answer here giving is
hygiene. What is the hygiene and write students is the science of health which
actually aims at preserving then maintaining and the improving. Yes the health
of the it is only individual, ya it is individual and the community as a whole
that is how can maintain a hygienic condition. Next important thing here is how
to remain a healthy or how to maintain a good
health and then very important thing practiced by us the first one , can
you guesses the first one going to be , yes very right that is balanced diet .
next important thing that is regular exercise
and yoga meditation etc. and next thing is maintain a personal hygiene ,next is right attitude of mind and
finally a cultivating a good habits all
if this maintain well help us to maintain a good health now if this all are not
maintained what is going to leading do,
yes it might your condition called
disease what is disease let us now to
defined that now disorder of structures
and functions basically other abnormal condition all of them collectively is called as disease
. Now in this module just we have to talk about a brief outline of that disease
but later taking about some example also. Now here in this module we have discuss
about the health and the basic concept of hygiene and also outline disease. Yes
in the next module we will talking about type of disease. Ya student we will right back in a next module. Bye
then thank you.
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KARNATAKA STATE BOARD XI PCMB Physics Demo Videos
Welcome
dear students welcome to the chapter thermodynamics in this chapter we start
with knowing the basic terminologies in
this module because understanding these basic terminologies we can understand the chapter better ok let’s
see what is the basic terminologies that we are going to studied in this
module very very basic terms involved in this chapter first of all
what do you mean by thermodynamics , thermodynamics is a branch of physics which deals basically
with the conversion of heat energy into
mechanical work or mechanical work into heat energy so it is the branch of
physics which deals with a transfer energy from one place to another and
conversion of heat energy into mechanical work or vice versa that is
thermodynamics for me. Let’s see a simple example I got a cylinder me with me
which is fitted with piston you can see on the screen and which has ideal gas
in it. I supply heat energy how much I supply heat energy dQ amount of heat
energy has been supplied and this energy what it does please observe that then
you understand the meaning of thermodynamics this dQ supplied increases the
volume of gas that is implies pushing the piston upward so dW amount of work is
done how much work will be done dW
amount of work is done so heat energy supply is converted into work and that is
what is thermodynamics all about yeah let’s
try to understand different types of system . what do you mean by thermodynamic
system surrounding all that thermodynamic system is the quantity of matter
certain quantity of matter having fixed identity and mass let’s see what is
that A certain quantity of matter part of the matter having fixed identity and
mass we call it thermodynamic system example, don’t think big about
thermodynamic system is little water you’re got going to boil that and then
that water becomes a system for you maybe I have gas in a cylinder that is a
system for me look at this example water in a beaker may be 50 cc water Is that
it is a system for you , you are expecting that , yes look at that In a
container I’ve got gas that is a system for me having fixed identity and mass let’s
see what is surrounding you must understand that anything other than the system
in this universe become surrounding matter outside the system that becomes
surroundings . so you have to understand that thermodynamic system continuously
interacts the matter outside the system and that matter outside the system we
are calling it as surrounding look at that delicious coffee may be a tea is
presented in the cup that is the system for me now this system is a tea or
coffee remember it interacts something outside matter outside and that part
which is outside the system we are calling it as surrounding we go into
different types of system right now what do you mean by open system , open
system involves exchange of heat energy and matter between system and
surrounding that system I m calling it as open system if there is exchange of
heat and matter takes place between system and surrounding call that system as
open system look at this piston and cylinder you can see in the picture which
has gas in it and you supply the heat energy when you supply heat energy you
can see that the gas expands work has been done yes excess heat energy is there
what happened to the excess heat energy that will got . so it has got exchange
of heat energy as well as matter and that system we are calling it is the open
system lets go to the closed system means what a system in which you have got
only action exchange of heat but not matter that is absolutely no matter
exchange yes, if the exchange is only heat energy not the matter between the
system and surrounding we call it as a closed system. cylinder provide with the
piston having the ideal gas you supply heat energy remember only the heat
energy exchange between the system and surrounding not the matter you can seen
that work has been done but there is no matter to exchange let’s see what is that
work done dW amount of work done but no
amount of matter exchanged between system and surrounding yes will know it
isolated system no exchange of heat and matter between the system and
surroundings let’s see that example no exchange of matter and heat between the
system and surroundings look at this thermally isolated system nothing is going
to inside neither heat not the matter the system is called as isolated
system non conducting wall … thank you.
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KARNATAKA STATE BOARD XI PCMB Maths Limits Demo Videos
Hi I'm Hari Prasad let us start the chapter limits
in this chapter we are going to learn how to find out the limit of the function and what
do we mean by limit of a function let us start module number one in this
particular module we are going to learn what is the meaning of the word tending
to let us start the chapter now meaning of X x tends a is what we have to learn
first so immediately the question that comes to my mind is what is the meaning
of X tending 2 or X tending to any particular
number a in general so it can be particularly X tending to 2, X tending 3
something like that so what is the meaning of that does it mean x is equal 2 does it mean know that x is equal to something
else so answer this particular question will consider the following example
consider boy who always covers fifty percent of the total distance that means
the boy covers five meter for the first time so where he will be he'll be at
five meter mark the boy will cover all fifty percent of the remaining five
meter that means he will cover all 2.5 meter for the second time third time he
will cover 1.25 meter and so on if this is the case when the boy will be
exactly on 10 meter mark can you predict the answer is the boy will be never on
10 meter mark but he's very close to 10 meter mark right similarly when we write X tending 2 we mean that X is very close to two
but it is not equal 2 consider the number line we have minus 1 0 1 2 3 and so on when x tends 2
to it can be close to two when I say close to two it can be from the left side
or it can be from the right side also write suppose if I say x tends 2 and if
X's or close to 2 from the left side then it can take the following values can
you get what are the values it can take x is equal to 1 .8 is possible it can
take 1.9 yes it is close to 2 ,1.99 yes it can take these values right and one
point nine nine nine yeah still very close to 2 and so on there are many
infinitely many values that it can take but when X tends to 2 if X is close to
two on the right then it can take the following values which are the values can
you guess the point 2.8 can take it can take 2.2 it can take 2.1 and 2.01 so on
it can take many other values right is so now the question is clear to us let
us now talk in case of general elements like X and a, let X be a variable is
the meaning of variable quantity which keeps changing and a be a constant with
the meaning of constant quantity which has a fixed value right if X takes the
value near Nearer to a then we say that e
tendens to a and we write it as X arrow mark
a We write it as does x tends to a note that in this case X cannot be equal
to A and we are not specifying any manner in which
X should approach a that means it can approach to a from left as well as it can
approach from right now when X tends to a from the left we have the following
situation if X approaches a taking all values less than a but Nearer to a then
we say that extends to a from the left we write this as extends to a and we put
a small minus over a this minus is not
to be used in any of the calculation similarly when X tends to a from the right
we have the following situation if X approaches a taking all the values greater
than a but nearer to you a then we say that x tends to a from the right and
rewrite it as x tends to a plus we write small plus sign over a like this is the notation that you need to remember
thank you.
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KARNATAKA STATE BOARD XI PCMB Chemistry Demo Videos
Hello
students welcome to the new chapter called state of matter in this chapter we
are going to learn some interesting facts about the word matter so in this
module will learn introduction to state of matter. let me start with the word
matter as we all know matter is anything
that occupies the space possesses mass
for example this chair and table or a glass of water or some balloon containing air so if I concentrate on this I
come across with the new classification that matter is going to get classified into three
different types that is called solid other one liquid and one more is called
gases so along with these three we having some more state of matter like plasma
boseeinstein condensate, fermionic condensate,
quark condensate thought wave along with these three so let me concentrate on
these three types called solid liquid
and gases . if u look at these pictures you can come across with the
some interesting facts that the faster picture is tightly bond nothing but solid second one is slightly distributed
nothing but liquid last one is completely dispersed nothing but gases so by
looking at this picture I think I can make out some interesting points with
respect to this point number 1 if I concentrate on shape for solid this is
perfect If I concentrate on liquid there
is no perfect shape if I concentrate on gas and similar to the liquid there is
no shape for gas also. If I concentrate on volume solid has got volume liquid
has got volume but there is no volume for gases. I got there intermolecular
force of attraction and on the word
about that nothing but this particular word is very much essential for these
two particular parameter for shape and volume so what is intermolecular force
of attraction it is the attraction between two atoms if it is very much strong
I will be having a solid shape but it is very ,very less then there is no shape
and there is no volume so if I concentrate on intermolecular force of
attraction it is very much strong in case of solids it is very weak in case of
liquids and very week in case of gases so If I want a next point nothing but
packing efficiency if I concentrate on packing solid are having closely packed
structure if I concentrate on liquid is loosely packed if I concentrate on
gases it is very loosely packed if I concentrate on next word called density we
know the word density what is density it is nothing but mass by volume . if I
concentrate on packing of this particular thing it is closely packed nothing
but mass by volume is more in case of solids . so in case of liquid it is
slightly less in case of gases it is very very less there for density is very
high in case of for solids and it is very least
in case of gases and is
intermediate to solids and gases in case of liquids. So in the next point we
are going to learn about the word called flow ability so the word of flow
ability means that is the ability to flow which is maximum in case of gases and
less in case of liquids least in case of solids. if I concentrate on
compressibility it is nothing but ability to get compressed it is very high in
case of gases and less in case of liquids
which is very least in case of solids . so there are main two parameters
or condition by which I think these particular matters or wearing those two are
temperature and pressure . if you concentrate on solid I can interconvert this
solid into liquid just by heating and I can interconvert this liquid into gas
just by heating so there is interesting phenomena that I can convert ice into
water this water into steam just by heating so temperature, so the temperature
is the main criteria to convert solid into liquid, liquid into gas similarly I
can convert gas into liquid, liquid into solid by applying pressure . so these
two are very interesting condition by
which I can convert a solid into liquid , liquid into gas now will concentrate
on a new concept where and temperature will play a waiter roll to convert gas
into liquid that means at the high temperature and low pressure gases will
exist at the low temperature and high pressure liquid will exist there for
transformation of liquid to gases can be done by wearing this two condition so
we have to concentrate on high temperature low pressure of gases low
temperature and high pressure for liquids .
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KARNATAKA STATE BOARD XI PCMB Biology Demo Videos
Hello
Students, I am Sarita, and, you and me today will study all about the plants.
In studying the plants in module 1, will study about the tissues the plant
tissues and students before we can go to the study of the tissues we need to
study 2 terms that is why we need to study about the tissues and where are we
studying about the tissues, look at that histology is the branch of biology
where we study all about the tissues and why do we study about the tissues
exactly to study about the internal structure and that is anatomy. The branch
of biology that deals with the study of the internal structures with that the
whole concept of plant tissues originated with work of the pioneers Nehemiah
Grew as well as Marcello Malpighi of whom Nehemiah Grew later was called the
father of plant anatomy and this rightly a 1mark question awfully asked in the
boards students, who is the father of plant anatomy? And that’s Nehemiah Grew.
Now what are plant tissues, there are group of cells or aggregation of cells
which perform a common function and they have a common origin. Plant tissues
basically can be classified into two types based upon the capacity to divide or
not and are been classified as Maristem. Maristem which are those cells, which
have the capacity to divide and again observe that students it’s a 1 mark question
awfully asked in the board. So Maristem are those tissues which are capable of
dividing have the capacity to divide they are constantly undergoing division.
They had no other work other than dividing. The second group of tissues called
them as permanent tissues and these are tissues which have stopped dividing or
incapable of division and they are assigned with a particular function to take
part in the plant body. Here we go on now. Before we study very clearly about
the tissues, let us study 2 more terms one of them is differentiation. Now
differentiation is refer students cells that is Meristematic tissues becoming
assigned as a function that is less specialize cells become more specialized
cells in order to perform a function, observe there Meristerms get themselves
differentiated to give rise to Pyrencyma which a permanent tissue, observe that
Meristems differentiate to become a permanent tissue. So they are form
permanent tissues which are performing a function. I move on to the next term
that is Dedefferentiation, now this reverse of differentiation, differentiated
cells revert back to the dividing stage that means pyrencyma which is a
permanent tissue becomes now a Meristematic in nature, look at that Meristerms
permanent tissues divide or Dedefferentiate to become Meristerms that is
permanent tissues which are assigned with the function, now start dividing and
awfully happens in last trees for increase of growth, Thank You.
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NEET & AIIMS 11th PCB Chemistry-Redox Reaction Demo Videos
Hello, students, let us continue our discussion on redox reactions. Now, in the last modules we will be discussing about calculation of equivalent weights of oxidising agents and reducing agents and we also defined a very important term z factor. Today we will continue to discuss some examples on equivalent weight calculation and then we will see two particular special cases FeC2O4 and Cu2S. Let us start with some examples.
Find the equivalent weight of KBrO3 and Br2 in the following reaction. Now, you can see that in this reaction 10 electrons are being exchanged. And we remember how we have to calculate z factor. So, let us begin with KBrO3. So, we can say that for 2 moles of KBrO3 number of electrons exchanged or rather gained in this case will be equal to 10. So, therefore we can say that for 1 mole of KBrO3, number of electrons gained. So, we can say that, so, we can say that for 1 mole of KBrO3, number of electrons gained will be equal to 10 by 2 that is 5. Now, the z factor of KBrO3 will be 5 and therefore equivalent weight will be equal to molecular weight of KBrO3 divided by 5. I am not getting the exact weight, I am just representing it symbolically and that is what is important. Now, for Br2 we see that the number of electrons exchanged are 10 and since there is only 1 mole of Br2 we need to see that there is only 10 electrons that we have to use. So, the z factor of bromine becomes 10 and equivalent weight will become molecular weight of bromine divided by 10.
Let us see the next example. When HNO3 is oxidised into ammonia means NH3, the equivalent weight of HNO3 will be how much? Now, HNO3 is being changed into ammonia. First of all we will write their oxidation number, nitrogen in HNO3 will be equal to plus 5, you know the algebraic method to calculate the oxidation numbers. Now, in ammonia the oxidation number of nitrogen is minus 3. So, we can see that, we can calculate the change in oxidation number, since there is only one atom of nitrogen it will be equal to plus 5 minus, minus minus 3 that is equal to plus 8. Keep in mind, change in oxidation number is initial oxidation number minus the final oxidation number. So, this 8 is there, this is what it will become the z factor and therefore equivalent weight is molecular weight divided by 8.
Let us see the next example. The equivalent weight of H2SO4 in the following reaction is. They have given us a redox reaction and in that they are asking for weight of H2SO4. Now, can I say that the z factor for H2SO4 will be equal to 2? Actually it would be wrong, why, because it is not an acid base reaction. It should be actually analysed like a redox reaction, which means we have to focus on the loss and gain of the electron. So, what should be your strategy? First we will find out the overall loss or gain of electrons in the redox reaction. It is like balancing, and with that process we have to get the loss or gain of electrons. To do this, we can either focus on SO2 or sodium dichromate that is Na2Cr2O7. Now, we will use this information to calculate the z factor of H2SO4. Just remember that there is only 1 mole of H2SO4 involved in the reaction. So, let us focus on the solution. The oxidation number of chromium in K2Cr2O7 is plus 6 and that in Cr2SO4 thrice is plus 3. Since there are two atoms of chromium we can see that the number of electrons exchanged overall will be equal to 6 and therefore we can say that for 1 mole of H2SO4 number of electrons exchanged will be also equal to 6. So, z factor of H2SO4 is 6 and the equivalent weight will be equal to molecular weight divided by 6. So, remember that in redox reaction acid and base equivalent weight will be got from loss or gain of electrons. Now, this calculation would also have been done, if you have just analysed SO2 to SO4 2 negative.
So, let us take a look at the next example. The equivalent weight of HNO3, molecular weight is 63, in the following reaction is. So, we have given a reaction between copper and HNO3 to give you copper nitrate and NO and H2. And we are having four options. Now, to analyse this reaction understand that HNO3 here is not just acting as an acid but it is also acting as an oxidising agent. So, HNO3 has dual roles, it is going to act as an oxidising agent and it will also provide the acidic medium. Now, we will find out the overall loss or gain of electrons. And to do this better would be copper because only oxidisation of copper is done. HNO3 is reducing, so, in HNO3 we have to observe NO very carefully. So, using this information we will calculate z factor and then we will get to the equivalent weight part. Let us see the solution. So, we can see that the oxidation number of Cu in copper is zero and that in copper nitrate is plus 2. Since there are 3 copper involved, we can see that the change in oxidation number is minus 6. Now, if we had to do NO, remember we have got only 2 NO corresponding to the change in oxidation number. So, we will find that nitrogen in HNO3 is plus 5 and that in NO is plus 2. So, the change in oxidation number is plus 6. Even if I do through copper or from HNO3 that means NO, from both the loss and gain of oxidation number will be 6 and it should be like that. So, number of electrons exchanged overall is 6 and therefore we can say for 8 moles of HNO3 number of electrons is equal to 6. For 1 mole of HNO3 it will be 6 by 8 that is 3 by 4. So, equivalent weight will be equal to molecular weight divided 3 by 4 or we can say it will be 63 times 4 by 3.
Now, let us focus on some special cases. We will focus on ferrous oxalate, FeC2O4. FeC2O4 is a good reducing agent. Now Fe2 positive is oxidised to Fe3 positive. Now, in this reaction we can see on the reactant side the charge is 2 positive and on the product side the charge is 3 positive. Now, to balance the charge since atoms are already balanced, to balance the charge we simply need to add an electron to the product side. Now, C2O4 negative 2 is oxidised to CO2 and we can see that here we will have to balance the atoms first. So, we just multiple the product side by 2. Now, to balance the charge, reactant side has got 2 negative charge and product side has 0. So, to balance the charge we simply add 2 electrons to the product side. Now, I am seeing both the reactions here that overall FeC2O4 both the components are oxidised. So, FeC2O4 overall loses a total of 3 electrons and hence equivalent weight of FeC2O4 will be equal to molecular weight divided by 3.
Now, let us see another special case, Cu2S, cupra sulphide. It is also a good reducing agent. Now, in this case Cu positive is oxidised to Cu 2positive. Again we will balance the charge. On the reactant side charge is 1 positive and on the product side charge is 2 positive. So, to balance the charge, we simply add an electron to the product side. Now, since there are 2 copper, we can say overall 2 electrons are lost for copper. Now, sulphide iron is oxidised to SO2. Now, first we will balance the atoms. So to do that, we have to add 2 H2O on the reactant side to balance the oxygen and 4H positive on the product side. Here we have assumed that medium is acidic in nature. So, we add these and then to balance the charge we see that the reactant side has a total charge of 2 negative and product side has 4 positive. To do this, we will now add 6 electrons to the product side and this balances the charge. So, 2 electrons of copper and 6 sulphide iron. So, Cu2S loses the total of 8 electrons and hence its equivalent weight will be equal to molecular weight divided by 8.
Thank you.
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